Question
($20.00) CORRECT ANSWERS
Found in Mathematics : Algebra

All calculations need to be typed out in moderate detail with explanations if necessary on word document.  I can transfer to turn in document.  Due by noon tomorrow PST.  

 

 

1.  Three years after purchase, a car is estimated to be worth $24,000.  At five years, its value is $19,000.  If the car is depreciating in a linear manner, write an equation that represents the depreciation of the car.  Answer the following questions:

            a. How much is the car depreciating each year?

            b. What was the purchase price of the car?

            c. If the car continues this rate of depreciation, what will its value be at year 10?

Calculations:

 

 

 

 

Answer: a._______________ 

                b._______________ 

                c._______________ 

 

2.  On a particular April day, the temperature at 8 am was 40°F.  By 4 pm the temperature was 64°F.  What was the hourly rate of temperature change?   

Calculations:

 

 

 

 

Answer: _______________ 

 

3.  The cost for an electrician is $135 for 3 hours.  A 7 hour repair costs $315.  Showing your calculations, determine the price of a 12 hour repair.

Calculations:

 

 

 

 

Answer: _______________ 

 

4.  Sarah has two part-time jobs and needs to earn at least $300 total per week.  Job A pays her $10 an hour and job B pays $7.50 an hour.  Write an inequality that represents this scenario.  Name and label your variables, such as Job A= x.

Calculations:

 

 

 

 

Answer: _______________ 

 

5.  A manufacturer produces a 4-cup and 8-cup coffee maker.  The 4-cup maker takes 6 hours to produce and the 8-cup takes 9 hours.  The manufacturer has at most 500 hours of labor per week. 

            a. Write an inequality to represent the number of each type of coffee makers they can produce in a week.

            b. Is it possible to produce 20 4-cup and 30 8-cup coffee makers in a given week?  Explain why or why not showing all of your calculations. 

Calculations:

 

 

 

Answer: a._______________ 

 

               b._______________  

Tutorial
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* Posted on 2/26/2014 9:11:32 AM


SOLUTION :   1.   a. BV at y3 = 24000 ($). BV at y5 = 19000 ($). So, depreciation in 2 years ( y5 - y3) = 24000 - 19000 = 5000 ($). Depreciation is by a straight line method.  => Depreciation per year = 5000 / 2 , = 2500 ($) (ANSWER).   b. Price ...

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